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200031011331 = 397168668387
BaseRepresentation
bin1011101001001011000…
…1110000001000000011
3201010022111122020001020
42322102301300020003
511234130414330311
6231520514440523
720310645354024
oct2722261601003
9633274566036
10200031011331
11779183224a8
1232925b93143
1315b2a889588
149978274c4b
15530b04cc06
hex2e92c70203

200031011331 has 8 divisors (see below), whose sum is σ = 266982692544. Its totient is φ = 133216668840.

The previous prime is 200031011321. The next prime is 200031011351. The reversal of 200031011331 is 133110130002.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 200031011331 - 210 = 200031010307 is a prime.

It is a super-3 number, since 3×2000310113313 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 200031011331.

It is not an unprimeable number, because it can be changed into a prime (200031011321) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 34331281 + ... + 34337106.

It is an arithmetic number, because the mean of its divisors is an integer number (33372836568).

Almost surely, 2200031011331 is an apocalyptic number.

200031011331 is a deficient number, since it is larger than the sum of its proper divisors (66951681213).

200031011331 is an equidigital number, since it uses as much as digits as its factorization.

200031011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68669361.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 200031011331 its reverse (133110130002), we get a palindrome (333141141333).

The spelling of 200031011331 in words is "two hundred billion, thirty-one million, eleven thousand, three hundred thirty-one".

Divisors: 1 3 971 2913 68668387 206005161 66677003777 200031011331