Base | Representation |
---|---|
bin | 10010101000110000… |
… | …101101100011110001 |
3 | 1220122121121211211201 |
4 | 102220300231203301 |
5 | 311440332222433 |
6 | 13105405411201 |
7 | 1305616326004 |
oct | 225060554361 |
9 | 56577554751 |
10 | 20011210993 |
11 | 8539897004 |
12 | 3a65869b01 |
13 | 1b6bb01767 |
14 | d7b9a353b |
15 | 7c1c32a7d |
hex | 4a8c2d8f1 |
20011210993 has 2 divisors, whose sum is σ = 20011210994. Its totient is φ = 20011210992.
The previous prime is 20011210987. The next prime is 20011211021. The reversal of 20011210993 is 39901211002.
It is an a-pointer prime, because the next prime (20011211021) can be obtained adding 20011210993 to its sum of digits (28).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 14212693089 + 5798517904 = 119217^2 + 76148^2 .
It is a cyclic number.
It is not a de Polignac number, because 20011210993 - 221 = 20009113841 is a prime.
It is not a weakly prime, because it can be changed into another prime (20011219993) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10005605496 + 10005605497.
It is an arithmetic number, because the mean of its divisors is an integer number (10005605497).
Almost surely, 220011210993 is an apocalyptic number.
It is an amenable number.
20011210993 is a deficient number, since it is larger than the sum of its proper divisors (1).
20011210993 is an equidigital number, since it uses as much as digits as its factorization.
20011210993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 28.
Adding to 20011210993 its reverse (39901211002), we get a palindrome (59912421995).
The spelling of 20011210993 in words is "twenty billion, eleven million, two hundred ten thousand, nine hundred ninety-three".
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