Base | Representation |
---|---|
bin | 101101100001011100000110… |
… | …100101111001001101001011 |
3 | 222020212220000220120022111112 |
4 | 231201130012211321031023 |
5 | 202220220100320144404 |
6 | 1545451113120120535 |
7 | 60112460500234106 |
oct | 5541340645711513 |
9 | 866786026508445 |
10 | 200210011099979 |
11 | 5887a6528900a1 |
12 | 1a55605b76614b |
13 | 879395268394a |
14 | 376230551773d |
15 | 1822dc636556e |
hex | b6170697934b |
200210011099979 has 2 divisors, whose sum is σ = 200210011099980. Its totient is φ = 200210011099978.
The previous prime is 200210011099951. The next prime is 200210011100023. The reversal of 200210011099979 is 979990110012002.
200210011099979 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-200210011099979 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (200210011099949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105005549989 + 100105005549990.
It is an arithmetic number, because the mean of its divisors is an integer number (100105005549990).
Almost surely, 2200210011099979 is an apocalyptic number.
200210011099979 is a deficient number, since it is larger than the sum of its proper divisors (1).
200210011099979 is an equidigital number, since it uses as much as digits as its factorization.
200210011099979 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 183708, while the sum is 50.
The spelling of 200210011099979 in words is "two hundred trillion, two hundred ten billion, eleven million, ninety-nine thousand, nine hundred seventy-nine".
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