Base | Representation |
---|---|
bin | 101101100001011100000110… |
… | …100101111001001101110111 |
3 | 222020212220000220120022120011 |
4 | 231201130012211321031313 |
5 | 202220220100320200043 |
6 | 1545451113120121051 |
7 | 60112460500234201 |
oct | 5541340645711567 |
9 | 866786026508504 |
10 | 200210011100023 |
11 | 5887a652890131 |
12 | 1a55605b766187 |
13 | 8793952683982 |
14 | 3762305517771 |
15 | 1822dc636559d |
hex | b61706979377 |
200210011100023 has 2 divisors, whose sum is σ = 200210011100024. Its totient is φ = 200210011100022.
The previous prime is 200210011099979. The next prime is 200210011100039. The reversal of 200210011100023 is 320001110012002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200210011100023 - 241 = 198010987844471 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 200210011099976 and 200210011100012.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200210011130023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100105005550011 + 100105005550012.
It is an arithmetic number, because the mean of its divisors is an integer number (100105005550012).
Almost surely, 2200210011100023 is an apocalyptic number.
200210011100023 is a deficient number, since it is larger than the sum of its proper divisors (1).
200210011100023 is an equidigital number, since it uses as much as digits as its factorization.
200210011100023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 200210011100023 its reverse (320001110012002), we get a palindrome (520211121112025).
The spelling of 200210011100023 in words is "two hundred trillion, two hundred ten billion, eleven million, one hundred thousand, twenty-three".
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