200211000112111 has 4 divisors (see below), whose sum is σ = 200309190894000. Its totient is φ = 200112809330224.

The previous prime is 200211000112093. The next prime is 200211000112133. The reversal of 200211000112111 is 111211000112002.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 200211000112111 - 2¹¹ = 200211000110063 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 200211000112091 and 200211000112100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (200211000712111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49095387886 + ... + 49095391963.

It is an arithmetic number, because the mean of its divisors is an integer number (50077297723500).

Almost surely, 2^{200211000112111} is an apocalyptic number.

200211000112111 is a deficient number, since it is larger than the sum of its proper divisors (98190781889).

200211000112111 is an equidigital number, since it uses as much as digits as its factorization.

200211000112111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 98190781888.

The product of its (nonzero) digits is 8, while the sum is 13.

Adding to 200211000112111 its reverse (111211000112002), we get a palindrome (311422000224113).

The spelling of 200211000112111 in words is "two hundred trillion, two hundred eleven billion, one hundred twelve thousand, one hundred eleven".