Base | Representation |
---|---|
bin | 101101100001011101000001… |
… | …100110011100111010111011 |
3 | 222020212222120220102121222110 |
4 | 231201131001212130322323 |
5 | 202220224112240231021 |
6 | 1545451355243223403 |
7 | 60112524151144314 |
oct | 5541350146347273 |
9 | 866788526377873 |
10 | 200211001102011 |
11 | 588800106a5299 |
12 | 1a556297217b63 |
13 | 8793a7c800173 |
14 | 376239abc160b |
15 | 1822e3321e476 |
hex | b6174199cebb |
200211001102011 has 32 divisors (see below), whose sum is σ = 283996589702400. Its totient is φ = 125024497274880.
The previous prime is 200211001101973. The next prime is 200211001102019. The reversal of 200211001102011 is 110201100112002.
It is not a de Polignac number, because 200211001102011 - 29 = 200211001101499 is a prime.
It is not an unprimeable number, because it can be changed into a prime (200211001102019) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 567670920 + ... + 568023498.
It is an arithmetic number, because the mean of its divisors is an integer number (8874893428200).
Almost surely, 2200211001102011 is an apocalyptic number.
200211001102011 is a deficient number, since it is larger than the sum of its proper divisors (83785588600389).
200211001102011 is a wasteful number, since it uses less digits than its factorization.
200211001102011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 405579.
The product of its (nonzero) digits is 8, while the sum is 12.
Adding to 200211001102011 its reverse (110201100112002), we get a palindrome (310412101214013).
Subtracting from 200211001102011 its reverse (110201100112002), we obtain a palindrome (90009900990009).
The spelling of 200211001102011 in words is "two hundred trillion, two hundred eleven billion, one million, one hundred two thousand, eleven".
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