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2002110012121 = 8231243240191
BaseRepresentation
bin11101001000100111000…
…011100101101011011001
321002101210111012120110011
4131020213003211223121
5230300310130341441
64131431233521521
7264435103211632
oct35104703455331
97071714176404
102002110012121
117020a99a815a
122840327132a1
13116a4b74945b
146cc8cbc4889
153712d371581
hex1d2270e5ad9

2002110012121 has 4 divisors (see below), whose sum is σ = 2002353260544. Its totient is φ = 2001866763700.

The previous prime is 2002110012113. The next prime is 2002110012127. The reversal of 2002110012121 is 1212100112002.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2002110012121 - 23 = 2002110012113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2002110012127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121611865 + ... + 121628326.

It is an arithmetic number, because the mean of its divisors is an integer number (500588315136).

Almost surely, 22002110012121 is an apocalyptic number.

It is an amenable number.

2002110012121 is a deficient number, since it is larger than the sum of its proper divisors (243248423).

2002110012121 is an equidigital number, since it uses as much as digits as its factorization.

2002110012121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 243248422.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 2002110012121 its reverse (1212100112002), we get a palindrome (3214210124123).

The spelling of 2002110012121 in words is "two trillion, two billion, one hundred ten million, twelve thousand, one hundred twenty-one".

Divisors: 1 8231 243240191 2002110012121