Base | Representation |
---|---|
bin | 1011101001110110010… |
… | …0001011000101010111 |
3 | 201010210010012110100102 |
4 | 2322131210023011113 |
5 | 11240013233013421 |
6 | 231550502004315 |
7 | 20315303634023 |
oct | 2723544130527 |
9 | 633703173312 |
10 | 200212001111 |
11 | 77a00500831 |
12 | 3297671669b |
13 | 15b59218b15 |
14 | 9994309383 |
15 | 531bd9e60b |
hex | 2e9d90b157 |
200212001111 has 2 divisors, whose sum is σ = 200212001112. Its totient is φ = 200212001110.
The previous prime is 200212001083. The next prime is 200212001113. The reversal of 200212001111 is 111100212002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 200212001111 - 218 = 200211738967 is a prime.
Together with 200212001113, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 200212001092 and 200212001101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200212001113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100106000555 + 100106000556.
It is an arithmetic number, because the mean of its divisors is an integer number (100106000556).
Almost surely, 2200212001111 is an apocalyptic number.
200212001111 is a deficient number, since it is larger than the sum of its proper divisors (1).
200212001111 is an equidigital number, since it uses as much as digits as its factorization.
200212001111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 200212001111 its reverse (111100212002), we get a palindrome (311312213113).
The spelling of 200212001111 in words is "two hundred billion, two hundred twelve million, one thousand, one hundred eleven".
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