Base | Representation |
---|---|
bin | 11101001001101001111… |
… | …100100011011011101111 |
3 | 21002111200200212201121012 |
4 | 131021221330203123233 |
5 | 230310104423211031 |
6 | 4132134443055435 |
7 | 264504651050243 |
oct | 35115174433357 |
9 | 7074620781535 |
10 | 2003232241391 |
11 | 702625415667 |
12 | 2842a651157b |
13 | 116b9a0b1144 |
14 | 6cd57c6c423 |
15 | 37196b48b2b |
hex | 1d269f236ef |
2003232241391 has 2 divisors, whose sum is σ = 2003232241392. Its totient is φ = 2003232241390.
The previous prime is 2003232241303. The next prime is 2003232241399. The reversal of 2003232241391 is 1931422323002.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2003232241391 - 222 = 2003228047087 is a prime.
It is a super-2 number, since 2×20032322413912 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2003232241399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1001616120695 + 1001616120696.
It is an arithmetic number, because the mean of its divisors is an integer number (1001616120696).
Almost surely, 22003232241391 is an apocalyptic number.
2003232241391 is a deficient number, since it is larger than the sum of its proper divisors (1).
2003232241391 is an equidigital number, since it uses as much as digits as its factorization.
2003232241391 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 2003232241391 its reverse (1931422323002), we get a palindrome (3934654564393).
The spelling of 2003232241391 in words is "two trillion, three billion, two hundred thirty-two million, two hundred forty-one thousand, three hundred ninety-one".
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