Base | Representation |
---|---|
bin | 101101100100011001011000… |
… | …000111011100110011011111 |
3 | 222021121022121102221200021111 |
4 | 231210121120013130303133 |
5 | 202232032310013021301 |
6 | 1550124323354242451 |
7 | 60133243655114032 |
oct | 5544313007346337 |
9 | 867538542850244 |
10 | 200413242313951 |
11 | 58948862584167 |
12 | 1a589519426427 |
13 | 87a9b70250044 |
14 | 376c0a47cb019 |
15 | 182831d301551 |
hex | b646581dccdf |
200413242313951 has 2 divisors, whose sum is σ = 200413242313952. Its totient is φ = 200413242313950.
The previous prime is 200413242313909. The next prime is 200413242314011. The reversal of 200413242313951 is 159313242314002.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 200413242313951 - 223 = 200413233925343 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (200413242313351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100206621156975 + 100206621156976.
It is an arithmetic number, because the mean of its divisors is an integer number (100206621156976).
Almost surely, 2200413242313951 is an apocalyptic number.
200413242313951 is a deficient number, since it is larger than the sum of its proper divisors (1).
200413242313951 is an equidigital number, since it uses as much as digits as its factorization.
200413242313951 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 40.
Adding to 200413242313951 its reverse (159313242314002), we get a palindrome (359726484627953).
The spelling of 200413242313951 in words is "two hundred trillion, four hundred thirteen billion, two hundred forty-two million, three hundred thirteen thousand, nine hundred fifty-one".
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