Base | Representation |
---|---|
bin | 101101101110100011100000… |
… | …010101011111111011110001 |
3 | 222101002001110010222021221010 |
4 | 231232203200111133323301 |
5 | 202330001431433300423 |
6 | 1551421132251021133 |
7 | 60234545542001433 |
oct | 5556434025377361 |
9 | 871061403867833 |
10 | 201111312400113 |
11 | 59097912985a45 |
12 | 1a68087773a7a9 |
13 | 882a93b91171b |
14 | 3793ba767c653 |
15 | 183b577c3c693 |
hex | b6e8e055fef1 |
201111312400113 has 32 divisors (see below), whose sum is σ = 272166405073920. Its totient is φ = 132076646507520.
The previous prime is 201111312400001. The next prime is 201111312400127. The reversal of 201111312400113 is 311004213111102.
It is a happy number.
It is not a de Polignac number, because 201111312400113 - 28 = 201111312399857 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 201111312400113.
It is not an unprimeable number, because it can be changed into a prime (201111312400183) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 268192608 + ... + 268941438.
It is an arithmetic number, because the mean of its divisors is an integer number (8505200158560).
Almost surely, 2201111312400113 is an apocalyptic number.
It is an amenable number.
201111312400113 is a deficient number, since it is larger than the sum of its proper divisors (71055092673807).
201111312400113 is a wasteful number, since it uses less digits than its factorization.
201111312400113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 752649.
The product of its (nonzero) digits is 144, while the sum is 21.
Adding to 201111312400113 its reverse (311004213111102), we get a palindrome (512115525511215).
The spelling of 201111312400113 in words is "two hundred one trillion, one hundred eleven billion, three hundred twelve million, four hundred thousand, one hundred thirteen".
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