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2012414504041 = 3659549990299
BaseRepresentation
bin11101010010001101010…
…000000110110001101001
321010101101121220222222001
4131102031100012301221
5230432411103112131
64140253534531001
7265251336022264
oct35221520066151
97111347828861
102012414504041
11706507584487
12286029666a61
13117a01548156
146d589569cdb
1537532d29261
hex1d48d406c69

2012414504041 has 4 divisors (see below), whose sum is σ = 2012964498000. Its totient is φ = 2011864510084.

The previous prime is 2012414504033. The next prime is 2012414504053. The reversal of 2012414504041 is 1404054142102.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2012414504041 - 23 = 2012414504033 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2012414504071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 274991491 + ... + 274998808.

It is an arithmetic number, because the mean of its divisors is an integer number (503241124500).

Almost surely, 22012414504041 is an apocalyptic number.

It is an amenable number.

2012414504041 is a deficient number, since it is larger than the sum of its proper divisors (549993959).

2012414504041 is an equidigital number, since it uses as much as digits as its factorization.

2012414504041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 549993958.

The product of its (nonzero) digits is 5120, while the sum is 28.

Adding to 2012414504041 its reverse (1404054142102), we get a palindrome (3416468646143).

The spelling of 2012414504041 in words is "two trillion, twelve billion, four hundred fourteen million, five hundred four thousand, forty-one".

Divisors: 1 3659 549990299 2012414504041