Base | Representation |
---|---|
bin | 10010101111110101… |
… | …111111010110101011 |
3 | 1220221220012201220010 |
4 | 102233311333112223 |
5 | 312211242110430 |
6 | 13125252303003 |
7 | 1311561322011 |
oct | 225765772653 |
9 | 56856181803 |
10 | 20130035115 |
11 | 859a975363 |
12 | 3a99611a63 |
13 | 1b8a6063a8 |
14 | d8d6948b1 |
15 | 7cc3a4cb0 |
hex | 4afd7f5ab |
20130035115 has 8 divisors (see below), whose sum is σ = 32208056208. Its totient is φ = 10736018720.
The previous prime is 20130035113. The next prime is 20130035153. The reversal of 20130035115 is 51153003102.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 20130035115 - 21 = 20130035113 is a prime.
It is a super-2 number, since 2×201300351152 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 20130035091 and 20130035100.
It is not an unprimeable number, because it can be changed into a prime (20130035113) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 671001156 + ... + 671001185.
It is an arithmetic number, because the mean of its divisors is an integer number (4026007026).
Almost surely, 220130035115 is an apocalyptic number.
20130035115 is a deficient number, since it is larger than the sum of its proper divisors (12078021093).
20130035115 is a wasteful number, since it uses less digits than its factorization.
20130035115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1342002349.
The product of its (nonzero) digits is 450, while the sum is 21.
Adding to 20130035115 its reverse (51153003102), we get a palindrome (71283038217).
The spelling of 20130035115 in words is "twenty billion, one hundred thirty million, thirty-five thousand, one hundred fifteen".
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