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BaseRepresentation
bin10010101111111001…
…101011011011110111
31220221222000212100111
4102233321223123313
5312212014031403
613125325123451
71311602460142
oct225771533367
956858025314
1020131002103
1185a0475923
123a999b9587
131b8a884584
14d8d867059
157cc4e656d
hex4afe6b6f7

20131002103 has 4 divisors (see below), whose sum is σ = 21006263088. Its totient is φ = 19255741120.

The previous prime is 20131002097. The next prime is 20131002139. The reversal of 20131002103 is 30120013102.

Adding to 20131002103 its reverse (30120013102), we get a palindrome (50251015205).

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 20131002103 - 29 = 20131001591 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20131002403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437630458 + ... + 437630503.

It is an arithmetic number, because the mean of its divisors is an integer number (5251565772).

Almost surely, 220131002103 is an apocalyptic number.

20131002103 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

20131002103 is a deficient number, since it is larger than the sum of its proper divisors (875260985).

20131002103 is an equidigital number, since it uses as much as digits as its factorization.

20131002103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 875260984.

The product of its (nonzero) digits is 36, while the sum is 13.

The spelling of 20131002103 in words is "twenty billion, one hundred thirty-one million, two thousand, one hundred three".

Divisors: 1 23 875260961 20131002103