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2013141124033 = 13221435558599
BaseRepresentation
bin11101010010111000100…
…011111100001111000001
321010110021021012010012121
4131102320203330033001
5230440403111432113
64140454012524241
7265305341134024
oct35227043741701
97113237163177
102013141124033
1170684a755876
122861b0a80681
13117ab8c47c00
146d617c731bb
1537576a08e8d
hex1d4b88fc3c1

2013141124033 has 12 divisors (see below), whose sum is σ = 2180927827200. Its totient is φ = 1857416638896.

The previous prime is 2013141124003. The next prime is 2013141124039. The reversal of 2013141124033 is 3304211413102.

Adding to 2013141124033 its reverse (3304211413102), we get a palindrome (5317352537135).

It is a de Polignac number, because none of the positive numbers 2k-2013141124033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2013141123989 and 2013141124007.

It is not an unprimeable number, because it can be changed into a prime (2013141124039) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2417133 + ... + 3141466.

It is an arithmetic number, because the mean of its divisors is an integer number (181743985600).

Almost surely, 22013141124033 is an apocalyptic number.

It is an amenable number.

2013141124033 is a deficient number, since it is larger than the sum of its proper divisors (167786703167).

2013141124033 is a wasteful number, since it uses less digits than its factorization.

2013141124033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5560768 (or 5560755 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

The spelling of 2013141124033 in words is "two trillion, thirteen billion, one hundred forty-one million, one hundred twenty-four thousand, thirty-three".