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BaseRepresentation
bin11101010010111000101…
…011110111011000010101
321010110021102002122200110
4131102320223313120111
5230440404124420201
64140454125233233
7265305364605141
oct35227053673025
97113242078613
102013143201301
11706850944521
122861b1702819
13117ab94c456b
146d618254221
1537576cb96d6
hex1d4b8af7615

2013143201301 has 4 divisors (see below), whose sum is σ = 2684190935072. Its totient is φ = 1342095467532.

The previous prime is 2013143201299. The next prime is 2013143201317. The reversal of 2013143201301 is 1031023413102.

Adding to 2013143201301 its reverse (1031023413102), we get a palindrome (3044166614403).

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2013143201301 - 21 = 2013143201299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2013143201701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 335523866881 + ... + 335523866886.

It is an arithmetic number, because the mean of its divisors is an integer number (671047733768).

Almost surely, 22013143201301 is an apocalyptic number.

It is an amenable number.

2013143201301 is a deficient number, since it is larger than the sum of its proper divisors (671047733771).

2013143201301 is an equidigital number, since it uses as much as digits as its factorization.

2013143201301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 671047733770.

The product of its (nonzero) digits is 432, while the sum is 21.

The spelling of 2013143201301 in words is "two trillion, thirteen billion, one hundred forty-three million, two hundred one thousand, three hundred one".

Divisors: 1 3 671047733767 2013143201301