Base | Representation |
---|---|
bin | 10010101111111110… |
… | …010101111111000001 |
3 | 1220222001022222210112 |
4 | 102233332111333001 |
5 | 312212322144321 |
6 | 13125411241105 |
7 | 1311616042262 |
oct | 225776257701 |
9 | 56861288715 |
10 | 20132224961 |
11 | 85a1130652 |
12 | 3a9a2a9195 |
13 | 1b8abc2064 |
14 | d8daa4969 |
15 | 7cc688a5b |
hex | 4aff95fc1 |
20132224961 has 2 divisors, whose sum is σ = 20132224962. Its totient is φ = 20132224960.
The previous prime is 20132224951. The next prime is 20132225021. The reversal of 20132224961 is 16942223102.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 18791200561 + 1341024400 = 137081^2 + 36620^2 .
It is a cyclic number.
It is not a de Polignac number, because 20132224961 - 26 = 20132224897 is a prime.
It is a super-2 number, since 2×201322249612 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (20132224901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10066112480 + 10066112481.
It is an arithmetic number, because the mean of its divisors is an integer number (10066112481).
Almost surely, 220132224961 is an apocalyptic number.
It is an amenable number.
20132224961 is a deficient number, since it is larger than the sum of its proper divisors (1).
20132224961 is an equidigital number, since it uses as much as digits as its factorization.
20132224961 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 32.
The spelling of 20132224961 in words is "twenty billion, one hundred thirty-two million, two hundred twenty-four thousand, nine hundred sixty-one".
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