Base | Representation |
---|---|
bin | 10010101111111111… |
… | …000000110100010001 |
3 | 1220222001122220110022 |
4 | 102233333000310101 |
5 | 312212343303101 |
6 | 13125415113225 |
7 | 1311620402621 |
oct | 225777006421 |
9 | 56861586408 |
10 | 20132400401 |
11 | 85a1240443 |
12 | 3a9a372815 |
13 | 1b8ac53b79 |
14 | d8db0c881 |
15 | 7cc6c0a1b |
hex | 4affc0d11 |
20132400401 has 4 divisors (see below), whose sum is σ = 20781832704. Its totient is φ = 19482968100.
The previous prime is 20132400349. The next prime is 20132400439. The reversal of 20132400401 is 10400423102.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-20132400401 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 20132400401.
It is not an unprimeable number, because it can be changed into a prime (20132400451) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 324716105 + ... + 324716166.
It is an arithmetic number, because the mean of its divisors is an integer number (5195458176).
Almost surely, 220132400401 is an apocalyptic number.
It is an amenable number.
20132400401 is a deficient number, since it is larger than the sum of its proper divisors (649432303).
20132400401 is an equidigital number, since it uses as much as digits as its factorization.
20132400401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 649432302.
The product of its (nonzero) digits is 192, while the sum is 17.
Adding to 20132400401 its reverse (10400423102), we get a palindrome (30532823503).
The spelling of 20132400401 in words is "twenty billion, one hundred thirty-two million, four hundred thousand, four hundred one".
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