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2013303102133 is a prime number
BaseRepresentation
bin11101010011000010001…
…101110101101010110101
321010110200112222110101111
4131103002031311222311
5230441221043232013
64140522040355021
7265312346002261
oct35230215655265
97113615873344
102013303102133
11706923129374
12286237175a71
13117b1367bb3b
146d6315990a1
1537585d5273d
hex1d4c2375ab5

2013303102133 has 2 divisors, whose sum is σ = 2013303102134. Its totient is φ = 2013303102132.

The previous prime is 2013303102127. The next prime is 2013303102143. The reversal of 2013303102133 is 3312013033102.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2001098818404 + 12204283729 = 1414602^2 + 110473^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013303102133 - 213 = 2013303093941 is a prime.

It is a super-2 number, since 2×20133031021332 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013303102143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006651551066 + 1006651551067.

It is an arithmetic number, because the mean of its divisors is an integer number (1006651551067).

Almost surely, 22013303102133 is an apocalyptic number.

It is an amenable number.

2013303102133 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013303102133 is an equidigital number, since it uses as much as digits as its factorization.

2013303102133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 2013303102133 its reverse (3312013033102), we get a palindrome (5325316135235).

The spelling of 2013303102133 in words is "two trillion, thirteen billion, three hundred three million, one hundred two thousand, one hundred thirty-three".