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2013310011197 is a prime number
BaseRepresentation
bin11101010011000010101…
…000001100011100111101
321010110201000222110211202
4131103002220030130331
5230441224330324242
64140522444425245
7265312461506312
oct35230250143475
97113630873752
102013310011197
11706927018241
12286239548225
13117b14c2a844
146d632476d09
1537586769932
hex1d4c2a0c73d

2013310011197 has 2 divisors, whose sum is σ = 2013310011198. Its totient is φ = 2013310011196.

The previous prime is 2013310011127. The next prime is 2013310011239. The reversal of 2013310011197 is 7911100133102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1765534042756 + 247775968441 = 1328734^2 + 497771^2 .

It is a cyclic number.

It is not a de Polignac number, because 2013310011197 - 212 = 2013310007101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2013310011127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1006655005598 + 1006655005599.

It is an arithmetic number, because the mean of its divisors is an integer number (1006655005599).

Almost surely, 22013310011197 is an apocalyptic number.

It is an amenable number.

2013310011197 is a deficient number, since it is larger than the sum of its proper divisors (1).

2013310011197 is an equidigital number, since it uses as much as digits as its factorization.

2013310011197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1134, while the sum is 29.

Adding to 2013310011197 its reverse (7911100133102), we get a palindrome (9924410144299).

The spelling of 2013310011197 in words is "two trillion, thirteen billion, three hundred ten million, eleven thousand, one hundred ninety-seven".