Base | Representation |
---|---|
bin | 101101110010110011100100… |
… | …100001100000011111010111 |
3 | 222102002222111001101222000211 |
4 | 231302303210201200133113 |
5 | 202344243221222324421 |
6 | 1552203244020350251 |
7 | 60264630002213020 |
oct | 5562634441403727 |
9 | 872088431358024 |
10 | 201403440433111 |
11 | 5919a7a0602994 |
12 | 1a709404845387 |
13 | 884c3558a7597 |
14 | 37a3d9b123c47 |
15 | 1843e742919e1 |
hex | b72ce48607d7 |
201403440433111 has 4 divisors (see below), whose sum is σ = 230175360494992. Its totient is φ = 172631520371232.
The previous prime is 201403440433109. The next prime is 201403440433193. The reversal of 201403440433111 is 111334044304102.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 201403440433111 - 21 = 201403440433109 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (201403440433411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14385960030930 + ... + 14385960030943.
It is an arithmetic number, because the mean of its divisors is an integer number (57543840123748).
Almost surely, 2201403440433111 is an apocalyptic number.
201403440433111 is a deficient number, since it is larger than the sum of its proper divisors (28771920061881).
201403440433111 is an equidigital number, since it uses as much as digits as its factorization.
201403440433111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28771920061880.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 201403440433111 its reverse (111334044304102), we get a palindrome (312737484737213).
The spelling of 201403440433111 in words is "two hundred one trillion, four hundred three billion, four hundred forty million, four hundred thirty-three thousand, one hundred eleven".
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