Base | Representation |
---|---|
bin | 11101011011001110100… |
… | …100000111001000011011 |
3 | 21011022101122021102202111 |
4 | 131123032210013020123 |
5 | 231112230122431021 |
6 | 4144535013013151 |
7 | 266043346056631 |
oct | 35331644071033 |
9 | 7138348242674 |
10 | 2022100202011 |
11 | 70a62793674a |
12 | 287a913241b7 |
13 | 1188b609aa96 |
14 | 6dc27a75351 |
15 | 378ed3008e1 |
hex | 1d6ce90721b |
2022100202011 has 4 divisors (see below), whose sum is σ = 2022106021624. Its totient is φ = 2022094382400.
The previous prime is 2022100202009. The next prime is 2022100202033. The reversal of 2022100202011 is 1102020012202.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2022100202011 - 21 = 2022100202009 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 2022100201982 and 2022100202000.
It is not an unprimeable number, because it can be changed into a prime (2022100202611) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2353110 + ... + 3095371.
It is an arithmetic number, because the mean of its divisors is an integer number (505526505406).
Almost surely, 22022100202011 is an apocalyptic number.
2022100202011 is a deficient number, since it is larger than the sum of its proper divisors (5819613).
2022100202011 is an equidigital number, since it uses as much as digits as its factorization.
2022100202011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5819612.
The product of its (nonzero) digits is 32, while the sum is 13.
Adding to 2022100202011 its reverse (1102020012202), we get a palindrome (3124120214213).
The spelling of 2022100202011 in words is "two trillion, twenty-two billion, one hundred million, two hundred two thousand, eleven".
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