Base | Representation |
---|---|
bin | 101111110000000110000100… |
… | …110001011111111111001111 |
3 | 1000112121001220000201211021102 |
4 | 233300012010301133333033 |
5 | 210011324110310103403 |
6 | 2022354430243253315 |
7 | 62143645644243434 |
oct | 5760060461377717 |
9 | 1015531800654242 |
10 | 210013243441103 |
11 | 60a0a130985713 |
12 | 1b679b8237a23b |
13 | 902521907328b |
14 | 39c09a396bb8b |
15 | 1942dd69beb88 |
hex | bf0184c5ffcf |
210013243441103 has 16 divisors (see below), whose sum is σ = 214205180229120. Its totient is φ = 205854417480096.
The previous prime is 210013243441093. The next prime is 210013243441207. The reversal of 210013243441103 is 301144342310012.
It is a cyclic number.
It is not a de Polignac number, because 210013243441103 - 246 = 139644499263439 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (210013243441403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6174278 + ... + 21404396.
It is an arithmetic number, because the mean of its divisors is an integer number (13387823764320).
Almost surely, 2210013243441103 is an apocalyptic number.
210013243441103 is a deficient number, since it is larger than the sum of its proper divisors (4191936788017).
210013243441103 is a wasteful number, since it uses less digits than its factorization.
210013243441103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15231206.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 210013243441103 its reverse (301144342310012), we get a palindrome (511157585751115).
The spelling of 210013243441103 in words is "two hundred ten trillion, thirteen billion, two hundred forty-three million, four hundred forty-one thousand, one hundred three".
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