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210034315410407 is a prime number
BaseRepresentation
bin101111110000011001101100…
…110000101011101111100111
31000112200002021120100202221222
4233300121230300223233213
5210012200234221113112
62022412233224530555
762145323064106325
oct5760315460535747
91015602246322858
10210034315410407
1160a18064514084
121b682083320a5b
1390271c6866077
1439c1a02376d15
15194371b8d6372
hexbf066cc2bbe7

210034315410407 has 2 divisors, whose sum is σ = 210034315410408. Its totient is φ = 210034315410406.

The previous prime is 210034315410397. The next prime is 210034315410421. The reversal of 210034315410407 is 704014513430012.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 210034315410407 - 210 = 210034315409383 is a prime.

It is a super-2 number, since 2×2100343154104072 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (210034315410467) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105017157705203 + 105017157705204.

It is an arithmetic number, because the mean of its divisors is an integer number (105017157705204).

Almost surely, 2210034315410407 is an apocalyptic number.

210034315410407 is a deficient number, since it is larger than the sum of its proper divisors (1).

210034315410407 is an equidigital number, since it uses as much as digits as its factorization.

210034315410407 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 35.

Adding to 210034315410407 its reverse (704014513430012), we get a palindrome (914048828840419).

The spelling of 210034315410407 in words is "two hundred ten trillion, thirty-four billion, three hundred fifteen million, four hundred ten thousand, four hundred seven".