Base | Representation |
---|---|
bin | 101111110000011001101100… |
… | …110000101011101111100111 |
3 | 1000112200002021120100202221222 |
4 | 233300121230300223233213 |
5 | 210012200234221113112 |
6 | 2022412233224530555 |
7 | 62145323064106325 |
oct | 5760315460535747 |
9 | 1015602246322858 |
10 | 210034315410407 |
11 | 60a18064514084 |
12 | 1b682083320a5b |
13 | 90271c6866077 |
14 | 39c1a02376d15 |
15 | 194371b8d6372 |
hex | bf066cc2bbe7 |
210034315410407 has 2 divisors, whose sum is σ = 210034315410408. Its totient is φ = 210034315410406.
The previous prime is 210034315410397. The next prime is 210034315410421. The reversal of 210034315410407 is 704014513430012.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 210034315410407 - 210 = 210034315409383 is a prime.
It is a super-2 number, since 2×2100343154104072 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (210034315410467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 105017157705203 + 105017157705204.
It is an arithmetic number, because the mean of its divisors is an integer number (105017157705204).
Almost surely, 2210034315410407 is an apocalyptic number.
210034315410407 is a deficient number, since it is larger than the sum of its proper divisors (1).
210034315410407 is an equidigital number, since it uses as much as digits as its factorization.
210034315410407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 35.
Adding to 210034315410407 its reverse (704014513430012), we get a palindrome (914048828840419).
The spelling of 210034315410407 in words is "two hundred ten trillion, thirty-four billion, three hundred fifteen million, four hundred ten thousand, four hundred seven".
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