Base | Representation |
---|---|

bin | 10011100101101010… |

… | …111100100111111011 |

3 | 2000021211111200202111 |

4 | 103211222330213323 |

5 | 321033434010021 |

6 | 13355032313151 |

7 | 1343135325304 |

oct | 234552744773 |

9 | 60254450674 |

10 | 21033110011 |

11 | 8a13707951 |

12 | 40abb427b7 |

13 | 1ca2738534 |

14 | 10375b17ab |

15 | 8317dc8e1 |

hex | 4e5abc9fb |

21033110011 has 2 divisors, whose sum is σ = 21033110012. Its totient is φ = 21033110010.

The previous prime is 21033109997. The next prime is 21033110023. The reversal of 21033110011 is 11001133012.

Adding to 21033110011 its reverse (11001133012), we get a palindrome (32034243023).

It can be divided in two parts, 21033 and 110011, that added together give a square (131044 = 362^{2}).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21033110011 - 2^{13} = 21033101819 is a prime.

It is a junction number, because it is equal to *n*+sod(*n*) for *n* = 21033109973 and 21033110000.

It is not a weakly prime, because it can be changed into another prime (21033110071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10516555005 + 10516555006.

It is an arithmetic number, because the mean of its divisors is an integer number (10516555006).

Almost surely, 2^{21033110011} is an apocalyptic number.

21033110011 is a deficient number, since it is larger than the sum of its proper divisors (1).

21033110011 is an equidigital number, since it uses as much as digits as its factorization.

21033110011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 18, while the sum is 13.

The spelling of 21033110011 in words is "twenty-one billion, thirty-three million, one hundred ten thousand, eleven".

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