Base | Representation |
---|---|
bin | 10011101011000010… |
… | …010110101011000111 |
3 | 2000112002220021212001 |
4 | 103223002112223013 |
5 | 321230010211403 |
6 | 13412010010131 |
7 | 1345310442343 |
oct | 235302265307 |
9 | 60462807761 |
10 | 21123132103 |
11 | 8a5a503877 |
12 | 4116116947 |
13 | 1cb8297548 |
14 | 1045526623 |
15 | 839670c1d |
hex | 4eb096ac7 |
21123132103 has 2 divisors, whose sum is σ = 21123132104. Its totient is φ = 21123132102.
The previous prime is 21123132089. The next prime is 21123132109. The reversal of 21123132103 is 30123132112.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21123132103 - 25 = 21123132071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21123132109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10561566051 + 10561566052.
It is an arithmetic number, because the mean of its divisors is an integer number (10561566052).
Almost surely, 221123132103 is an apocalyptic number.
21123132103 is a deficient number, since it is larger than the sum of its proper divisors (1).
21123132103 is an equidigital number, since it uses as much as digits as its factorization.
21123132103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 21123132103 its reverse (30123132112), we get a palindrome (51246264215).
Subtracting 21123132103 from its reverse (30123132112), we obtain a palindrome (9000000009).
The spelling of 21123132103 in words is "twenty-one billion, one hundred twenty-three million, one hundred thirty-two thousand, one hundred three".
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