Base | Representation |
---|---|
bin | 10011101011011100… |
… | …100110011010101101 |
3 | 2000112120211211202101 |
4 | 103223130212122231 |
5 | 321233240343313 |
6 | 13412413255101 |
7 | 1345423066333 |
oct | 235334463255 |
9 | 60476754671 |
10 | 21130012333 |
11 | 8a63383011 |
12 | 4118494491 |
13 | 1cb98360a1 |
14 | 10463d7b53 |
15 | 83a07e5dd |
hex | 4eb7266ad |
21130012333 has 4 divisors (see below), whose sum is σ = 21130504668. Its totient is φ = 21129520000.
The previous prime is 21130012291. The next prime is 21130012339. The reversal of 21130012333 is 33321003112.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 8441566884 + 12688445449 = 91878^2 + 112643^2 .
It is a cyclic number.
It is not a de Polignac number, because 21130012333 - 217 = 21129881261 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 21130012333.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21130012339) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 174916 + ... + 269917.
It is an arithmetic number, because the mean of its divisors is an integer number (5282626167).
Almost surely, 221130012333 is an apocalyptic number.
It is an amenable number.
21130012333 is a deficient number, since it is larger than the sum of its proper divisors (492335).
21130012333 is an equidigital number, since it uses as much as digits as its factorization.
21130012333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 492334.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 21130012333 its reverse (33321003112), we get a palindrome (54451015445).
The spelling of 21130012333 in words is "twenty-one billion, one hundred thirty million, twelve thousand, three hundred thirty-three".
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