Base | Representation |
---|---|
bin | 10011101011011100… |
… | …101101001011010111 |
3 | 2000112120220020201221 |
4 | 103223130231023113 |
5 | 321233242240043 |
6 | 13412414031211 |
7 | 1345423243141 |
oct | 235334551327 |
9 | 60476806657 |
10 | 21130040023 |
11 | 8a633a18a4 |
12 | 41184a8507 |
13 | 1cb9845881 |
14 | 1046403c91 |
15 | 83a0878ed |
hex | 4eb72d2d7 |
21130040023 has 4 divisors (see below), whose sum is σ = 21130364608. Its totient is φ = 21129715440.
The previous prime is 21130039999. The next prime is 21130040069. The reversal of 21130040023 is 32004003112.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21130040023 - 25 = 21130039991 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21130039979 and 21130040006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21130049023) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27111 + ... + 207352.
It is an arithmetic number, because the mean of its divisors is an integer number (5282591152).
Almost surely, 221130040023 is an apocalyptic number.
21130040023 is a deficient number, since it is larger than the sum of its proper divisors (324585).
21130040023 is an equidigital number, since it uses as much as digits as its factorization.
21130040023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 324584.
The product of its (nonzero) digits is 144, while the sum is 16.
Adding to 21130040023 its reverse (32004003112), we get a palindrome (53134043135).
The spelling of 21130040023 in words is "twenty-one billion, one hundred thirty million, forty thousand, twenty-three".
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