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2113121431301 is a prime number
BaseRepresentation
bin11110101111111111110…
…110100010111100000101
321111000100001202222002212
4132233333312202330011
5234110133041300201
64254430553513205
7305445055543226
oct36577766427405
97430301688085
102113121431301
11745195a60491
122a1654112805
1312436065103a
14743c044924d
1539e79153abb
hex1ebffda2f05

2113121431301 has 2 divisors, whose sum is σ = 2113121431302. Its totient is φ = 2113121431300.

The previous prime is 2113121431277. The next prime is 2113121431307. The reversal of 2113121431301 is 1031341213112.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2015746852900 + 97374578401 = 1419770^2 + 312049^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2113121431301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2113121431307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1056560715650 + 1056560715651.

It is an arithmetic number, because the mean of its divisors is an integer number (1056560715651).

Almost surely, 22113121431301 is an apocalyptic number.

It is an amenable number.

2113121431301 is a deficient number, since it is larger than the sum of its proper divisors (1).

2113121431301 is an equidigital number, since it uses as much as digits as its factorization.

2113121431301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 2113121431301 its reverse (1031341213112), we get a palindrome (3144462644413).

The spelling of 2113121431301 in words is "two trillion, one hundred thirteen billion, one hundred twenty-one million, four hundred thirty-one thousand, three hundred one".