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BaseRepresentation
bin1100010101110101110…
…0011001000100110011
3202021021010010220212101
43011131130121010303
511433204401340311
6241222352241231
721214036536655
oct3053534310463
9667233126771
10212021121331
1181a10439618
1235111540217
1316cbb96a616
14a39483a6d5
hex315d719133

212021121331 has 2 divisors, whose sum is σ = 212021121332. Its totient is φ = 212021121330.

The previous prime is 212021121311. The next prime is 212021121343. The reversal of 212021121331 is 133121120212.

Adding to 212021121331 its reverse (133121120212), we get a palindrome (345142241543).

212021121331 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212021121331 is a prime.

It is a super-2 number, since 2×2120211213312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 212021121299 and 212021121308.

It is not a weakly prime, because it can be changed into another prime (212021121311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106010560665 + 106010560666.

It is an arithmetic number, because the mean of its divisors is an integer number (106010560666).

Almost surely, 2212021121331 is an apocalyptic number.

212021121331 is a deficient number, since it is larger than the sum of its proper divisors (1).

212021121331 is an equidigital number, since it uses as much as digits as its factorization.

212021121331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 19.

The spelling of 212021121331 in words is "two hundred twelve billion, twenty-one million, one hundred twenty-one thousand, three hundred thirty-one".