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213024414013 = 585736370909
BaseRepresentation
bin1100011001100100111…
…1101001100100111101
3202100212001000110200121
43012121033221210331
511442233222222023
6241510112254541
721250641433345
oct3063117514475
9670761013617
10213024414013
1182385801224
1235351541451
131711b78b428
14a44bba3d25
15581bae9d5d
hex31993e993d

213024414013 has 4 divisors (see below), whose sum is σ = 213060790780. Its totient is φ = 212988037248.

The previous prime is 213024413993. The next prime is 213024414017. The reversal of 213024414013 is 310414420312.

Adding to 213024414013 its reverse (310414420312), we get a palindrome (523438834325).

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 137235425209 + 75788988804 = 370453^2 + 275298^2 .

It is a cyclic number.

It is not a de Polignac number, because 213024414013 - 25 = 213024413981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213024414017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18179598 + ... + 18191311.

It is an arithmetic number, because the mean of its divisors is an integer number (53265197695).

Almost surely, 2213024414013 is an apocalyptic number.

It is an amenable number.

213024414013 is a deficient number, since it is larger than the sum of its proper divisors (36376767).

213024414013 is an equidigital number, since it uses as much as digits as its factorization.

213024414013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36376766.

The product of its (nonzero) digits is 2304, while the sum is 25.

The spelling of 213024414013 in words is "two hundred thirteen billion, twenty-four million, four hundred fourteen thousand, thirteen".

Divisors: 1 5857 36370909 213024414013