Base | Representation |
---|---|
bin | 1100011001100100111… |
… | …1101011000100100011 |
3 | 202100212001000210002012 |
4 | 3012121033223010203 |
5 | 11442233222421011 |
6 | 241510112343135 |
7 | 21250641460235 |
oct | 3063117530443 |
9 | 670761023065 |
10 | 213024420131 |
11 | 82385805886 |
12 | 35351544aab |
13 | 1711b791153 |
14 | a44bba6255 |
15 | 581baeba8b |
hex | 31993eb123 |
213024420131 has 4 divisors (see below), whose sum is σ = 225555268392. Its totient is φ = 200493571872.
The previous prime is 213024420121. The next prime is 213024420139. The reversal of 213024420131 is 131024420312.
213024420131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-213024420131 is a prime.
It is a super-2 number, since 2×2130244201312 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 213024420097 and 213024420106.
It is not an unprimeable number, because it can be changed into a prime (213024420139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6265424105 + ... + 6265424138.
It is an arithmetic number, because the mean of its divisors is an integer number (56388817098).
Almost surely, 2213024420131 is an apocalyptic number.
213024420131 is a deficient number, since it is larger than the sum of its proper divisors (12530848261).
213024420131 is a wasteful number, since it uses less digits than its factorization.
213024420131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12530848260.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 213024420131 its reverse (131024420312), we get a palindrome (344048840443).
The spelling of 213024420131 in words is "two hundred thirteen billion, twenty-four million, four hundred twenty thousand, one hundred thirty-one".
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