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21312123000000 = 2635671014863
BaseRepresentation
bin1001101100010000111011…
…00001010101010011000000
32210110102022111101011111220
410312020131201111103000
510243134211442000000
6113154353143435040
74326515163344520
oct466103541252300
983412274334456
1021312123000000
116877469911598
122482522a55a80
13bb7955b7a251
145397258c1680
1526e59d2261a0
hex13621d8554c0

21312123000000 has 392 divisors, whose sum is σ = 80553798898176. Its totient is φ = 4871337600000.

The previous prime is 21312122999983. The next prime is 21312123000013. The reversal of 21312123000000 is 32121312.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 20492569 + ... + 21507431.

Almost surely, 221312123000000 is an apocalyptic number.

21312123000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 21312123000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (40276899449088).

21312123000000 is an abundant number, since it is smaller than the sum of its proper divisors (59241675898176).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

21312123000000 is an frugal number, since it uses more digits than its factorization.

21312123000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1014915 (or 1014880 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 21312123000000 its reverse (32121312), we get a palindrome (21312155121312).

The spelling of 21312123000000 in words is "twenty-one trillion, three hundred twelve billion, one hundred twenty-three million", and thus it is an aban number.