Search a number
BaseRepresentation
bin1001101100010010111101…
…11011001111100010111111
32210110112010222011100112121
410312021132323033202333
510243143433344424411
6113155054102543411
74326554316341602
oct466113673174277
983415128140477
1021313220311231
11687798225a782
12248278a437b67
13bb7a9c2c9134
145397cb520339
1526e61472a571
hex13625eecf8bf

21313220311231 has 2 divisors, whose sum is σ = 21313220311232. Its totient is φ = 21313220311230.

The previous prime is 21313220311199. The next prime is 21313220311247. The reversal of 21313220311231 is 13211302231312.

Adding to 21313220311231 its reverse (13211302231312), we get a palindrome (34524522542543).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21313220311231 - 25 = 21313220311199 is a prime.

It is a super-2 number, since 2×213132203112312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21313220311196 and 21313220311205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21313220318231) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656610155615 + 10656610155616.

It is an arithmetic number, because the mean of its divisors is an integer number (10656610155616).

Almost surely, 221313220311231 is an apocalyptic number.

21313220311231 is a deficient number, since it is larger than the sum of its proper divisors (1).

21313220311231 is an equidigital number, since it uses as much as digits as its factorization.

21313220311231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 25.

The spelling of 21313220311231 in words is "twenty-one trillion, three hundred thirteen billion, two hundred twenty million, three hundred eleven thousand, two hundred thirty-one".