Base | Representation |
---|---|
bin | 110000011111111011001101… |
… | …111101100011101001011111 |
3 | 1000222020021220012100022101111 |
4 | 300133323031331203221133 |
5 | 210424202122024220111 |
6 | 2033352420055322451 |
7 | 62633265564241354 |
oct | 6037731575435137 |
9 | 1028207805308344 |
10 | 213300121320031 |
11 | 61a67089842929 |
12 | 1bb0abab080427 |
13 | 9203165c428a5 |
14 | 3a95ad0d2c62b |
15 | 199d65b89ba21 |
hex | c1fecdf63a5f |
213300121320031 has 4 divisors (see below), whose sum is σ = 213300155212200. Its totient is φ = 213300087427864.
The previous prime is 213300121319993. The next prime is 213300121320067. The reversal of 213300121320031 is 130023121003312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 213300121320031 - 231 = 213297973836383 is a prime.
It is a super-2 number, since 2×2133001213200312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 213300121319984 and 213300121320011.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (213300121320331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4419076 + ... + 21121753.
It is an arithmetic number, because the mean of its divisors is an integer number (53325038803050).
Almost surely, 2213300121320031 is an apocalyptic number.
213300121320031 is a deficient number, since it is larger than the sum of its proper divisors (33892169).
213300121320031 is an equidigital number, since it uses as much as digits as its factorization.
213300121320031 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33892168.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 213300121320031 its reverse (130023121003312), we get a palindrome (343323242323343).
The spelling of 213300121320031 in words is "two hundred thirteen trillion, three hundred billion, one hundred twenty-one million, three hundred twenty thousand, thirty-one".
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