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22114000153 = 710393040561
BaseRepresentation
bin10100100110000110…
…001101110100011001
32010002011101121021201
4110212012031310121
5330242141001103
614054203434201
71412001620440
oct244606156431
963064347251
1022114000153
11941885a693
124351b25961
132115657cbb
1410dad77d57
1589664b51d
hex52618dd19

22114000153 has 8 divisors (see below), whose sum is σ = 25297475840. Its totient is φ = 18936607680.

The previous prime is 22114000147. The next prime is 22114000159. The reversal of 22114000153 is 35100041122.

It is an interprime number because it is at equal distance from previous prime (22114000147) and next prime (22114000159).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 22114000153 - 213 = 22113991961 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 22114000153.

It is not an unprimeable number, because it can be changed into a prime (22114000159) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1513008 + ... + 1527553.

It is an arithmetic number, because the mean of its divisors is an integer number (3162184480).

Almost surely, 222114000153 is an apocalyptic number.

It is an amenable number.

22114000153 is a deficient number, since it is larger than the sum of its proper divisors (3183475687).

22114000153 is a wasteful number, since it uses less digits than its factorization.

22114000153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3041607.

The product of its (nonzero) digits is 240, while the sum is 19.

Adding to 22114000153 its reverse (35100041122), we get a palindrome (57214041275).

The spelling of 22114000153 in words is "twenty-two billion, one hundred fourteen million, one hundred fifty-three", and thus it is an aban number.

Divisors: 1 7 1039 7273 3040561 21283927 3159142879 22114000153