Search a number
BaseRepresentation
bin110011001100110000011101…
…001011111011011111001001
31002112021201021201220121110121
4303030300131023323133021
5214003300031433424233
62114524522443543241
765300334562314325
oct6314603513733711
91075251251817417
10225177035061193
1165826053a36676
122130899952ab21
139885145c21747
143d868ab746985
151b075888d492d
hexcccc1d2fb7c9

225177035061193 has 2 divisors, whose sum is σ = 225177035061194. Its totient is φ = 225177035061192.

The previous prime is 225177035061163. The next prime is 225177035061197. The reversal of 225177035061193 is 391160530771522.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 212265172678329 + 12911862382864 = 14569323^2 + 3593308^2 .

It is a cyclic number.

It is not a de Polignac number, because 225177035061193 - 221 = 225177032964041 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 225177035061193.

It is not a weakly prime, because it can be changed into another prime (225177035061197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 112588517530596 + 112588517530597.

It is an arithmetic number, because the mean of its divisors is an integer number (112588517530597).

Almost surely, 2225177035061193 is an apocalyptic number.

It is an amenable number.

225177035061193 is a deficient number, since it is larger than the sum of its proper divisors (1).

225177035061193 is an equidigital number, since it uses as much as digits as its factorization.

225177035061193 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2381400, while the sum is 52.

The spelling of 225177035061193 in words is "two hundred twenty-five trillion, one hundred seventy-seven billion, thirty-five million, sixty-one thousand, one hundred ninety-three".