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231113 = 239967
BaseRepresentation
bin111000011011001001
3102202000202
4320123021
524343423
64541545
71651541
oct703311
9382022
10231113
11148703
12b18b5
138126c
1460321
1548728
hex386c9

231113 has 4 divisors (see below), whose sum is σ = 232320. Its totient is φ = 229908.

The previous prime is 231109. The next prime is 231131. The reversal of 231113 is 311132.

231113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 231113 - 22 = 231109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 231094 and 231103.

It is not an unprimeable number, because it can be changed into a prime (231613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245 + ... + 722.

It is an arithmetic number, because the mean of its divisors is an integer number (58080).

2231113 is an apocalyptic number.

It is an amenable number.

231113 is a deficient number, since it is larger than the sum of its proper divisors (1207).

231113 is an equidigital number, since it uses as much as digits as its factorization.

231113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1206.

The product of its digits is 18, while the sum is 11.

The square root of 231113 is about 480.7421346210. The cubic root of 231113 is about 61.3679277375.

Adding to 231113 its reverse (311132), we get a palindrome (542245).

It can be divided in two parts, 2 and 31113, that multiplied together give a palindrome (62226).

The spelling of 231113 in words is "two hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 239 967 231113