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24000113 is a prime number
BaseRepresentation
bin101101110001…
…1011001110001
31200011022222002
41123203121301
522121000423
62214223345
7410666114
oct133433161
950138862
1024000113
1112602705
128054b55
134c84067
14328a57b
152191228
hex16e3671

24000113 has 2 divisors, whose sum is σ = 24000114. Its totient is φ = 24000112.

The previous prime is 24000089. The next prime is 24000131. The reversal of 24000113 is 31100042.

It is a happy number.

Together with next prime (24000131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16908544 + 7091569 = 4112^2 + 2663^2 .

It is a cyclic number.

It is not a de Polignac number, because 24000113 - 26 = 24000049 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 24000094 and 24000103.

It is not a weakly prime, because it can be changed into another prime (24000143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12000056 + 12000057.

It is an arithmetic number, because the mean of its divisors is an integer number (12000057).

Almost surely, 224000113 is an apocalyptic number.

It is an amenable number.

24000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

24000113 is an equidigital number, since it uses as much as digits as its factorization.

24000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 24000113 is about 4898.9910185670. The cubic root of 24000113 is about 288.4503667669.

Adding to 24000113 its reverse (31100042), we get a palindrome (55100155).

The spelling of 24000113 in words is "twenty-four million, one hundred thirteen", and thus it is an aban number.