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240113 is a prime number
BaseRepresentation
bin111010100111110001
3110012101002
4322213301
530140423
65051345
72020016
oct724761
9405332
10240113
11154445
12b6b55
13853a3
146370d
154b228
hex3a9f1

240113 has 2 divisors, whose sum is σ = 240114. Its totient is φ = 240112.

The previous prime is 240109. The next prime is 240131. The reversal of 240113 is 311042.

It is a happy number.

Together with next prime (240131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 223729 + 16384 = 473^2 + 128^2 .

It is a cyclic number.

It is not a de Polignac number, because 240113 - 22 = 240109 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 240094 and 240103.

It is not a weakly prime, because it can be changed into another prime (240173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120056 + 120057.

It is an arithmetic number, because the mean of its divisors is an integer number (120057).

2240113 is an apocalyptic number.

It is an amenable number.

240113 is a deficient number, since it is larger than the sum of its proper divisors (1).

240113 is an equidigital number, since it uses as much as digits as its factorization.

240113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 11.

The square root of 240113 is about 490.0132651266. The cubic root of 240113 is about 62.1544018463.

Adding to 240113 its reverse (311042), we get a palindrome (551155).

It can be divided in two parts, 2401 and 13, that multiplied together give a palindrome (31213).

The spelling of 240113 in words is "two hundred forty thousand, one hundred thirteen".