Base | Representation |
---|---|
bin | 100011000110011110110… |
… | …000000100011000010011 |
3 | 22112121011012001212022211 |
4 | 203012132300010120103 |
5 | 304010030323212120 |
6 | 5044042152412551 |
7 | 336162036106435 |
oct | 43063660043023 |
9 | 8477135055284 |
10 | 2412140054035 |
11 | 84aa8a1a3498 |
12 | 32b5a49a7157 |
13 | 14660506302a |
14 | 84a690ca655 |
15 | 42b2a5ae25a |
hex | 2319ec04613 |
2412140054035 has 16 divisors (see below), whose sum is σ = 3003422826240. Its totient is φ = 1857787269120.
The previous prime is 2412140054033. The next prime is 2412140054057. The reversal of 2412140054035 is 5304500412142.
It is not a de Polignac number, because 2412140054035 - 21 = 2412140054033 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a junction number, because it is equal to n+sod(n) for n = 2412140053988 and 2412140054006.
It is not an unprimeable number, because it can be changed into a prime (2412140054033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40286650 + ... + 40346479.
It is an arithmetic number, because the mean of its divisors is an integer number (187713926640).
Almost surely, 22412140054035 is an apocalyptic number.
2412140054035 is a deficient number, since it is larger than the sum of its proper divisors (591282772205).
2412140054035 is a wasteful number, since it uses less digits than its factorization.
2412140054035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 80633358.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 2412140054035 its reverse (5304500412142), we get a palindrome (7716640466177).
The spelling of 2412140054035 in words is "two trillion, four hundred twelve billion, one hundred forty million, fifty-four thousand, thirty-five".
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