Base | Representation |
---|---|
bin | 110110110111100100011100… |
… | …111010000100110110011111 |
3 | 1011122102022121101101201200212 |
4 | 312313210130322010312133 |
5 | 223112133434430341111 |
6 | 2213121433005443035 |
7 | 101554206416505545 |
oct | 6667443472046637 |
9 | 1148368541351625 |
10 | 241313222512031 |
11 | 6a9873aa0a35aa |
12 | 23094151b7047b |
13 | a48597c15c697 |
14 | 438389d7b5d95 |
15 | 1cd719d93798b |
hex | db791ce84d9f |
241313222512031 has 2 divisors, whose sum is σ = 241313222512032. Its totient is φ = 241313222512030.
The previous prime is 241313222511983. The next prime is 241313222512069. The reversal of 241313222512031 is 130215222313142.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 241313222512031 - 218 = 241313222249887 is a prime.
It is a super-2 number, since 2×2413132225120312 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (241313222112031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 120656611256015 + 120656611256016.
It is an arithmetic number, because the mean of its divisors is an integer number (120656611256016).
Almost surely, 2241313222512031 is an apocalyptic number.
241313222512031 is a deficient number, since it is larger than the sum of its proper divisors (1).
241313222512031 is an equidigital number, since it uses as much as digits as its factorization.
241313222512031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 32.
Adding to 241313222512031 its reverse (130215222313142), we get a palindrome (371528444825173).
The spelling of 241313222512031 in words is "two hundred forty-one trillion, three hundred thirteen billion, two hundred twenty-two million, five hundred twelve thousand, thirty-one".
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