2413401213441 has 4 divisors (see below), whose sum is σ = 3217868284592. Its totient is φ = 1608934142292.

The previous prime is 2413401213439. The next prime is 2413401213469. The reversal of 2413401213441 is 1443121043142.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 2413401213441 - 2¹ = 2413401213439 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2413401213399 and 2413401213408.

It is not an unprimeable number, because it can be changed into a prime (2413401218441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 402233535571 + ... + 402233535576.

It is an arithmetic number, because the mean of its divisors is an integer number (804467071148).

Almost surely, 2^{2413401213441} is an apocalyptic number.

It is an amenable number.

2413401213441 is a deficient number, since it is larger than the sum of its proper divisors (804467071151).

2413401213441 is an equidigital number, since it uses as much as digits as its factorization.

2413401213441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 804467071150.

The product of its (nonzero) digits is 9216, while the sum is 30.

Adding to 2413401213441 its reverse (1443121043142), we get a palindrome (3856522256583).

The spelling of 2413401213441 in words is "two trillion, four hundred thirteen billion, four hundred one million, two hundred thirteen thousand, four hundred forty-one".