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243113010141 = 3233347801159
BaseRepresentation
bin1110001001101010101…
…0100010001111011101
3212020111222000112002210
43202122222202033131
512440343412311031
6303403511311033
723364365330061
oct3423252421735
9766458015083
10243113010141
1194115a578a1
123b14a07b479
1319c05303471
14baa3cb1aa1
1564cd3c4746
hex389aaa23dd

243113010141 has 8 divisors (see below), whose sum is σ = 325541885760. Its totient is φ = 161379737312.

The previous prime is 243113010037. The next prime is 243113010143. The reversal of 243113010141 is 141010311342.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 243113010141 - 27 = 243113010013 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243113010143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 173899881 + ... + 173901278.

It is an arithmetic number, because the mean of its divisors is an integer number (40692735720).

Almost surely, 2243113010141 is an apocalyptic number.

It is an amenable number.

243113010141 is a deficient number, since it is larger than the sum of its proper divisors (82428875619).

243113010141 is a wasteful number, since it uses less digits than its factorization.

243113010141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 347801395.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 243113010141 its reverse (141010311342), we get a palindrome (384123321483).

The spelling of 243113010141 in words is "two hundred forty-three billion, one hundred thirteen million, ten thousand, one hundred forty-one".

Divisors: 1 3 233 699 347801159 1043403477 81037670047 243113010141