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243121205551 = 7164249211457
BaseRepresentation
bin1110001001101100100…
…1110011000100101111
3212020112112102220002111
43202123021303010233
512440403012034201
6303404403104451
723364525102310
oct3423311630457
9766475386074
10243121205551
119411a645164
123b150972127
1319c06c12813
14baa5006607
1564cde92b51
hex389b27312f

243121205551 has 8 divisors (see below), whose sum is σ = 277855812000. Its totient is φ = 208387350528.

The previous prime is 243121205539. The next prime is 243121205573. The reversal of 243121205551 is 155502121342.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 243121205551 - 215 = 243121172783 is a prime.

It is a super-3 number, since 3×2431212055513 (a number of 35 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (243121205581) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1044015 + ... + 1255471.

It is an arithmetic number, because the mean of its divisors is an integer number (34731976500).

Almost surely, 2243121205551 is an apocalyptic number.

243121205551 is a deficient number, since it is larger than the sum of its proper divisors (34734606449).

243121205551 is a wasteful number, since it uses less digits than its factorization.

243121205551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 375713.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 243121205551 its reverse (155502121342), we get a palindrome (398623326893).

The spelling of 243121205551 in words is "two hundred forty-three billion, one hundred twenty-one million, two hundred five thousand, five hundred fifty-one".

Divisors: 1 7 164249 211457 1149743 1480199 34731600793 243121205551