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243121245355 = 548624249071
BaseRepresentation
bin1110001001101100100…
…1111100110010101011
3212020112112111220200201
43202123021330302223
512440403014322410
6303404404013031
723364525326332
oct3423311746253
9766475456621
10243121245355
119411a67205a
123b150991177
1319c06c27981
14baa5016d19
1564cde9e83a
hex389b27ccab

243121245355 has 4 divisors (see below), whose sum is σ = 291745494432. Its totient is φ = 194496996280.

The previous prime is 243121245347. The next prime is 243121245397. The reversal of 243121245355 is 553542121342.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 243121245355 - 23 = 243121245347 is a prime.

It is a super-3 number, since 3×2431212453553 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24312124531 + ... + 24312124540.

It is an arithmetic number, because the mean of its divisors is an integer number (72936373608).

Almost surely, 2243121245355 is an apocalyptic number.

243121245355 is a deficient number, since it is larger than the sum of its proper divisors (48624249077).

243121245355 is an equidigital number, since it uses as much as digits as its factorization.

243121245355 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48624249076.

The product of its digits is 144000, while the sum is 37.

Adding to 243121245355 its reverse (553542121342), we get a palindrome (796663366697).

The spelling of 243121245355 in words is "two hundred forty-three billion, one hundred twenty-one million, two hundred forty-five thousand, three hundred fifty-five".

Divisors: 1 5 48624249071 243121245355