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243130131997 is a prime number
BaseRepresentation
bin1110001001101110101…
…1110110011000011101
3212020120011020101212121
43202123223312120131
512440412303210442
6303405322302541
723364664011034
oct3423353663035
9766504211777
10243130131997
1194124691795
123b153957a51
1319c08a1983c
14baa628b71b
1564ceb57967
hex389baf661d

243130131997 has 2 divisors, whose sum is σ = 243130131998. Its totient is φ = 243130131996.

The previous prime is 243130131983. The next prime is 243130132039. The reversal of 243130131997 is 799131031342.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 228427599481 + 14702532516 = 477941^2 + 121254^2 .

It is a cyclic number.

It is not a de Polignac number, because 243130131997 - 27 = 243130131869 is a prime.

It is a super-2 number, since 2×2431301319972 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (243130131697) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121565065998 + 121565065999.

It is an arithmetic number, because the mean of its divisors is an integer number (121565065999).

Almost surely, 2243130131997 is an apocalyptic number.

It is an amenable number.

243130131997 is a deficient number, since it is larger than the sum of its proper divisors (1).

243130131997 is an equidigital number, since it uses as much as digits as its factorization.

243130131997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 122472, while the sum is 43.

The spelling of 243130131997 in words is "two hundred forty-three billion, one hundred thirty million, one hundred thirty-one thousand, nine hundred ninety-seven".