Base | Representation |
---|---|
bin | 1110001001101110101… |
… | …1110110011000011101 |
3 | 212020120011020101212121 |
4 | 3202123223312120131 |
5 | 12440412303210442 |
6 | 303405322302541 |
7 | 23364664011034 |
oct | 3423353663035 |
9 | 766504211777 |
10 | 243130131997 |
11 | 94124691795 |
12 | 3b153957a51 |
13 | 19c08a1983c |
14 | baa628b71b |
15 | 64ceb57967 |
hex | 389baf661d |
243130131997 has 2 divisors, whose sum is σ = 243130131998. Its totient is φ = 243130131996.
The previous prime is 243130131983. The next prime is 243130132039. The reversal of 243130131997 is 799131031342.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 228427599481 + 14702532516 = 477941^2 + 121254^2 .
It is a cyclic number.
It is not a de Polignac number, because 243130131997 - 27 = 243130131869 is a prime.
It is a super-2 number, since 2×2431301319972 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (243130131697) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 121565065998 + 121565065999.
It is an arithmetic number, because the mean of its divisors is an integer number (121565065999).
Almost surely, 2243130131997 is an apocalyptic number.
It is an amenable number.
243130131997 is a deficient number, since it is larger than the sum of its proper divisors (1).
243130131997 is an equidigital number, since it uses as much as digits as its factorization.
243130131997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 122472, while the sum is 43.
The spelling of 243130131997 in words is "two hundred forty-three billion, one hundred thirty million, one hundred thirty-one thousand, nine hundred ninety-seven".
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