247433 has 2 divisors, whose sum is σ = 247434. Its totient is φ = 247432.

The previous prime is 247421. The next prime is 247439. The reversal of 247433 is 334742.

Adding to 247433 its sum of digits (23), we get a triangular number (247456 = T_{703}).

It is a happy number.

247433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 222784 + 24649 = 472^2 + 157^2 .

It is a cyclic number.

It is not a de Polignac number, because 247433 - 2^{6} = 247369 is a prime.

It is a super-2 number, since 2×247433^{2} = 122446178978, which contains 22 as substring.

It is a d-powerful number, because it can be written as **2**^{15} + **4** + **4**^{5} + **7**^{5} + **3**^{9} + **3**^{11} .

It is a plaindrome in base 11.

It is a nialpdrome in base 8.

It is a junction number, because it is equal to *n*+sod(*n*) for *n* = 247399 and 247408.

It is an inconsummate number, since it does not exist a number *n* which divided by its sum of digits gives 247433.

It is not a weakly prime, because it can be changed into another prime (247439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 123716 + 123717.

It is an arithmetic number, because the mean of its divisors is an integer number (123717).

2^{247433} is an apocalyptic number.

It is an amenable number.

247433 is a deficient number, since it is larger than the sum of its proper divisors (1).

247433 is an equidigital number, since it uses as much as digits as its factorization.

247433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2016, while the sum is 23.

The square root of 247433 is about 497.4263764619. The cubic root of 247433 is about 62.7796957904.

The spelling of 247433 in words is "two hundred forty-seven thousand, four hundred thirty-three".

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