Base | Representation |
---|---|
bin | 100100100010101011010… |
… | …001111111111010000101 |
3 | 22220001200021121221022211 |
4 | 210202223101333322011 |
5 | 312120300414214023 |
6 | 5201333235423421 |
7 | 346265153156554 |
oct | 44425321777205 |
9 | 8801607557284 |
10 | 2511134523013 |
11 | 888a69a78216 |
12 | 346811a54b71 |
13 | 152a50449bac |
14 | 8977a79dd9b |
15 | 454c13c3a0d |
hex | 248ab47fe85 |
2511134523013 has 2 divisors, whose sum is σ = 2511134523014. Its totient is φ = 2511134523012.
The previous prime is 2511134523011. The next prime is 2511134523017. The reversal of 2511134523013 is 3103254311152.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2473847685409 + 37286837604 = 1572847^2 + 193098^2 .
It is a cyclic number.
It is not a de Polignac number, because 2511134523013 - 21 = 2511134523011 is a prime.
Together with 2511134523011, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2511134523011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1255567261506 + 1255567261507.
It is an arithmetic number, because the mean of its divisors is an integer number (1255567261507).
Almost surely, 22511134523013 is an apocalyptic number.
It is an amenable number.
2511134523013 is a deficient number, since it is larger than the sum of its proper divisors (1).
2511134523013 is an equidigital number, since it uses as much as digits as its factorization.
2511134523013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10800, while the sum is 31.
Adding to 2511134523013 its reverse (3103254311152), we get a palindrome (5614388834165).
The spelling of 2511134523013 in words is "two trillion, five hundred eleven billion, one hundred thirty-four million, five hundred twenty-three thousand, thirteen".
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