252313044545 has 4 divisors (see below), whose sum is σ = 302775653460. Its totient is φ = 201850435632.

The previous prime is 252313044541. The next prime is 252313044569. The reversal of 252313044545 is 545440313252.

252313044545 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 182473354561 + 69839689984 = 427169^2 + 264272^2 .

It is a cyclic number.

It is not a de Polignac number, because 252313044545 - 2² = 252313044541 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 252313044499 and 252313044508.

It is not an unprimeable number, because it can be changed into a prime (252313044541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25231304450 + ... + 25231304459.

It is an arithmetic number, because the mean of its divisors is an integer number (75693913365).

Almost surely, 2^252313044545 is an apocalyptic number.

It is an amenable number.

252313044545 is a deficient number, since it is larger than the sum of its proper divisors (50462608915).

252313044545 is an equidigital number, since it uses as much as digits as its factorization.

252313044545 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50462608914.

The product of its (nonzero) digits is 288000, while the sum is 38.

Adding to 252313044545 its reverse (545440313252), we get a palindrome (797753357797).

The spelling of 252313044545 in words is "two hundred fifty-two billion, three hundred thirteen million, forty-four thousand, five hundred forty-five".